If 100 measures of common air be put to 36 of pure nitrous gas ..., after a few minutes the whole will be reduced to 79 or 80 measures, and exhibit no signs of either oxygenous or nitrous gas. If 100 measures of common air be admitted to 72 of nitrous gas ..., there will, as before, be found 79 or 80 measures of pure azotic gas for a residuum. ... These facts clearly point out the theory of the process: the elements of oxygen may combine with a certain portion of nitrous gas, or with twice that portion, but with no intermediate quantity. ...a) When Dalton says "measures" he is talking about volumes. Let us suppose that his measures were mL, and let us suppose further that he carried out this experiment at 20°C and 1.00 atm. How many moles of oxygen (O2) and nitrous gas (NO) would have been used in these experiments? Note: "Common air" is about 20% oxygen by volume.
|Back to the Classic Calculations home page|
|Back to the top of the Classic Chemistry site|