% data for Exercise Set 1.3 ex = input('Exercise number (1,2,11-16,25-29,31)? '); if ex == 1 u = [-1;2], v = [-3;-1] elseif ex == 2 u = [3;2], v = [2;-1] elseif ex==11 a1 = [1;-2;0], a2 = [0;1;2], a3 = [5;-6;8], b = [2;-1;6] disp('Given a vector equation xa1 + ya2 + za3 = b, where a1,a2,a3 and b are vectors,') disp(' the augmented matrix for the associated system of equations is formed by') disp(' the MATLAB command M = [a1 a2 a3 b] This places the column vectors') disp(' into a matrix M which is then available for study with MATLAB.') elseif ex==12 a1 = [1;-2;2], a2 = [0;5;5], a3 = [2;0;8], b = [-5;11;-7] disp('Given a vector equation xa1 + ya2 + za3 = b, where a1,a2,a3 and b are vectors,') disp(' the augmented matrix for the associated system of equations is formed by') disp(' the MATLAB command M = [a1 a2 a3 b] This places the column vectors') disp(' into a matrix M which is then available for study with MATLAB.') elseif ex==13 A = [1 -4 2;0 3 5;-2 8 -4], b = [3;-7;-3] disp('The columns of A are A(:,1), A(:,2), and A(:,3). Try typing them. The') disp(' vector equation you need to solve is xA(:,1) + yA(:,2) + zA(:,3) = b. ') disp(' So you can use the four vectors to form an augmented matrix:') disp(' M = [A(:,1) A(:,2) A(:,3) b]') disp(' (Can you devise an easier way to construct this matrix?)') elseif ex==14 A = [1 -2 -6;0 3 7;1 -2 5], b = [11;-5;9] disp('Try Exercise 13 first if you need help constructing the augmented matrix.') elseif ex==15 v1 = [7;1;-6], v2 = [-5;3;0] elseif ex==16 v1 = [3;0;2], v2 = [-2;0;3] elseif ex==25 A = [1 0 -4;0 3 -2;-2 6 3], b = [4;1;-4], a1 = A(:,1), a2 = A(:,2), a3 = A(:,3) elseif ex==26 A = [2 0 6;-1 8 5;1 -2 1], b = [10;3;3], a1 = A(:,1), a2 = A(:,2), a3 = A(:,3) elseif ex==27 v1 = [20;550], v2 = [30;500], b = [150;2825], A = [20 30;550 500] elseif ex==28 v1 = [27.6;3100;250], v2 = [30.2;6400;360], b=[162;23610;1623] elseif ex==29 v1 = [5;-4;3], v2 = [4;3;-2], v3 = [-4;-3;-1], v4 = [-9;8;6] elseif ex==31 v1 = [0;1], v2 = [8;1], v3 = [2;4], m=3 else disp('No data for this exercise in Section 1.3.') end